Soo confused on how to factor this: (𝑥) = 𝑥^3 + 6𝑥^2 − 13𝑥 − 42
Is that supposed to be f(x) = x^3 + 6x^2 − 13x − 42 or x = x^3 + 6x^2 − 13x − 42
@TheSmartOne The 2nd one.
Subtract x on both sides first
@TheSmartOne So It would be like 0=x^3+6x^2-12x-42
-13x - x = -x(13 + 1) = -x(14) = -14x So, it should be -14x not -12x. Do you understand? :)
@TheSmartOne Ohh Okay! Yeah I understand. Thanks!
Now, we should have: x^3 + 6x^2 - 14x - 42 = 0 And it cannot be factored
Can't is such a brash word
From the beginning x^3+6x^2-13x-42 Try picking out a factor of 42 and incorporating x
Clue: try x+2
Just about anything can be factored.
f(x) = x^3 + 6x^2 − 13x − 42 does factor over the set of Integers.
x^3 + 6x^2 − 13x − 42 = (x + 7) * (x^2 - x - 6) = (x + 7) * (x - 3) * (x + 2) @JBBADsunsaregrreat Look at this and see if you think it is correct.
That's why I asked in my first reply if he meant x or f(x). :P
@Directrix Yeah I think that is correct! Thanks so much I was getting really frustrated haha
@Directrix If you can, can you show me how to start the problem to come to that answer?
@TheSmartOne Sorry must've made a mistake!
@JBBADsunsaregrreat When you copied and pasted the problem, the lead "f" that goes with the (x) to be f(x) was deleted. The posted problem looked like this: x = x^3 + 6x^2 − 13x − 42 That is different from f(x) = x^3 + 6x^2 − 13x − 42. Always look back and check the problem you are about to post after the copy and paste procedure.
@JBBADsunsaregrreat I began by using the Rational Root Theorem.
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