Question

@ganeshie8

Answer 1

least power resistor

Answer 2

start by finding the current \(i\) in the circuit

Answer 3

to find the current, you need the value of overall resistance

Answer 4

ok I got this
would that be 1/r1+1/r2 etc? or just add the values because I get those two confused

Answer 5

The resistors are connected in series. So you just add them to get the overall resistance

Answer 6

oh ok it equals 6

Answer 7

series arrangement is like this
http://c8.alamy.com/comp/F7EJH9/epa05044018-nepalese-school-children-and-students-join-hands-as-they-F7EJH9.jpg

Answer 8

Yes,
R = 6
V = 12

i = ?

Answer 9

12/6=2?

Answer 10

so this 2A current flows through each of the resistor

Answer 11

you can find the power dissipation in each resistor by using i^2R

Answer 12

ok so I have to multiply 2 by each value?

Answer 13

i^2*R

Answer 14

2^2*2.2=8.8
2^2*1.1=4.4
2^2*2.7=10.8

Answer 15

which resistor draws the least power ?

Answer 16

R2 thank you :)

Answer 17

since the current is same through each resistor in a series network, the resistor with the "smallest resistance" draws the "least power".

Answer 18

so R2 is correct right?