Question

Which sequence is modeled by the graph below?


an = one third(27)n − 1
an = 27(one third)n − 1
an = one third(3)n − 1
an = 3(one half)n − 1

Answer 1

@ganeshie8 Please please help

Answer 2

@sleepyjess @imqwerty Help please.... I never really understood it! Please!

Answer 3

The answers in an easier form:
\[\frac{ 1 }{ 3 }(27)^{n-1}\]
\[27(\frac{ 1 }{ 3 })^{n-1} \]
\[\frac{ 1 }{ 3 }(3)^{n-1}\]
\[3(\frac{ 1 }{ 2 })^{n-1}\]

Answer 4

Hi @sleepyjess Do you understand this question? I didn't really excel in this lesson and never fully captured what I was supposed to do?

Answer 5

Not really, and I kinda have some homework to do *innocently whistles* maybe @perl could help

Answer 6

@perl Could you please help me?

Answer 7

@ganeshie8 Hi can you please help me?

Answer 8

Maybe @zepdrix ?

Answer 9

@zepdrix can you help

Answer 10

Hi @zepdrix can you help me with this question?

Answer 11

Let's look at that first coordinate provided,
it gives us a lot of information.
(2,1)

Answer 12

Which option satisfies that coordinate?
It's a nice easy one to plug in.

Answer 13

The last one?

Answer 14

\[\large\rm (2,1):\frac13(27)^{2-1}\]Does the first one work out ok?

Answer 15

The answer when you plug it in would be 8.9999

Answer 16

It would be 9,
I'm not sure how you ended up with 8.9999 LOL
but anyway, that's not the 1 that we needed.
The input value was 2,
the output was supposed to be 1.

So option 1 is no good.

Answer 17

Oh ok, I understand everything so far... The next thing I have to do is input it in all the sequences to see which one has an outcome of 1.... Right?

Answer 18

Im not really sure

Answer 19

Yes, input a 2 in each option,
see which ones give you an output of 1.

We might end up with more than one which satisfies this,
so you'll have to check all of them.

Answer 20

I am going out on a limb here... I think the answer is C.

Answer 21

Because when you input it, it comes with an outcome of 1

Answer 22

I THINK

Answer 23

That was the only one that worked?
Ah yes, it appears so.

Good job! :)

Answer 24

Thank you soo much! I really needed help in this question and you helped me understand!