One question help please i need to submit this asap
@rebeccaxhawaii
@SerenityJustice74 @HyperPiper
@mathmale why cant I ask any questions unless its to a qualified helper?
Pls share any thoughts you may have regarding what to do first.
i have no clue :( i really dont understand this and my teacher is on a plane rn so i cant call her
personally I would solve this and then find out the coordinate where they touched. If you multiply the second equation by -2 then you should be able to use elimination :)
I know that ill "have to pay" for a qualified helper @mathmale but look I have no "post" option
well first off 8x - 9 = -1x then 4x - 1 = 3x
whats next :)
okay so multiply (4x-1=y)-4
Rearrange your 4x - 1 = 3x so that both x terms are on the left side of your equation and your sole constant is on the right side.
were did you get 4x-1=3x?
so next is 3x - 4 ???????
or is it 3x * -4
You have 2 equtions that begin with "y=," so why not set those 2 equations = to each other? This will eliminate y and leave y ou with x only.
Please show every step of your work.
THAT ISNT THE EQUATION
im confused
@RhondaSommer I sent u a pm
look at your equations. write them out for me
Y = 8x - 9 Y = 4x - 1
okay, now multiply \[(y=4x-1)-2\] and you get \[-2y=-8x+2\]
@RhondaSommer ok whats next ???????
Altho there are various ways in which to solve a system of linear equations, I recommend using one that ELIMINATES one of the variables. The very last result, above, doesn't accomplish that. Name your method, then demonstrate its application to this problem.
so now you have \[y=8x-9\]and\[-2y=-8x+2\] combine them together :) \[-2y+y=8x-8x+2-9\]and you simplify to\[-y=-7\]which simplifies to \[y=7\]
is that everything :D
now, place (7) in place of (y) in the equation \[y=8x-9\] what do you get for (x)
2
this look good ????? @RhondaSommer
we stated that 4x-1 DID NOT equal 3x. I feel like your pulling that out of thin air. 4x-1=-y
none of that is what i put down either :/ I feel like you arent following me.
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