AN/MEDAL/TESTIMONY Quadratic Equations
What is the equation of the axis of symmetry if the x-intercepts are (-4,0) and (10,0)? Explanation please! Thank you! ^u^
what is half way between \(-4\) and \(10\)?
which is another way of asking "what is the average of -4 and 10?"
Half way between -4 and 10? I don't understand, but I would think it's somewhere around the number 5?
somewhere around that yes, but not there
same as saying what is \[\frac{-4+10}{2}\]
Here it is x = -3
This would be the answer the teacher would be looking for!
Oh! Well thank you, but I need an explanation too!
careful here
just because the roots are \(10\) and \(-4\) dots not mean the quadratic is \[(x-10)(x+4)\]
but it does mean the axis of symmetry is half way between those two roots since the average of \(10\) and \(-4\) is \[\frac{10-4}{2}=3\] that means the axis of symmetry is \(x=3\)
Okay Since we know the x-intercepts as -4 and 10 We can replug it back into the factor form, x=-4 this becomes (x+4) and x=10 becomes (x-10) we take (x+4) multiply by (x-10) we now get the quadratic equation Take the quadratic equation into the form ax^2 + bx +c Use the formula for axis of symmetry as x = b/2a
@satellite73 We only are certain its a quadratic when we multiply them out
it might be \[(x+4)(x-10)\] but it also might be \[2\pi(x+4)(x-10)\]
and we are certain it is a quadratic because they say it has to roots and an axis of symmetry
*two roots
Yeup
Oh! Thank you!
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