i need help to do this the last one was marked as wrong i didnt know a dashed line was needed plz help
Do you know how to graph the line y=x+3 ?
Do you know how to identify the slope and y-intercept of the graph that will given by the function f(x)=x+3 ?
i dont know
f(x)=mx+b tells us the slope is m and the y-intercept is (0,b)
so can you identify m and b?
for that dont you have to substitute 0 for x ?
to identity m and b no but you could do that to find the y-intercept but you do not have do any math to compare f(x)=mx+b to f(x)=x+3 to identify m and b
what values for m and b would make mx+b the same as x+3 ?
slope 1 and y int 3?
yes the slope m is 1 and the y-intercept is (0,b) or (0,3) in this case
So plot the point (0,3) first
That will a point on the y-axis between 2 and 4
then use your slope to plot another point
that would be (0,1)?
and connect the dots with a dashed line since you have < or > you would use a solid line if you had a line underneath the inquality like \[\ge \text{ or } \le\]
how did you get the point (0,1)?
because of the slope 1 i thought (0,1)?
slope=rise/run
sorry sorry its (1,0)
you have slope=1=1/1=rise/run rise once from your y-intercept and run once then you have your next point
like this @myininaya
no you have drawn a line with a negative slope we have a positive slope
1/1 can you put your finger on (0,3)?
now use your finger and go up once and to the right once
since the slope is 1/1
this?
i re made it does it look right
you are still now doing what I ask :( put your finger on (0,3) and we are going to find another point by using the slope which is 1/1 which tells us from the y-intercept we are going to rise up once and move right once can you do this?
tell me what position your finger lays when you do this
position/coordinates
is that (2,5)?
what is 3+1?
4 so its now set at (1,4)
you did it yes if you use the slope 1/1 to find another point from (0,3) you should get (1,4) conned those dots with a broken line
connect*
there is one part to this graph
y<x+3 means we want to shade everything below the line y=x+3 since < means less than if we had y>x+3 instead this would mean we want to shade everything above the line y=x+3 since > means greater than
its incorrect according to the homework
can i see what you entered?
what i had done before and the message
where is the shading part?
did you read what I said about the shading part above?
y<x+3 means y-coordinates of every point is less than y=x+3 this means you need to shade everything below the broken line you have for y=x+3
so how would i do that (0,3) and do i go down to the left
if you had y>x+3 this means we would shade everything above the broken line y=x+3
you already drew a broken line at y=x+3 ...
you only need to shade below the line
|dw:1461517969899:dw| you still need to shade below the line to show all the points that are a solution of y<x+3
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