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OpenStudy (tylermckinney16):
Questions here.
OpenStudy (tylermckinney16):
@Directrix
OpenStudy (ijlal):
the equation of a circle is
\[(x-a)^2 + (y-b)^2 = r^2\]
where (a,b) is the center of the circle and r is the radius(distance between the center to the circumference)
OpenStudy (ijlal):
what do you think is the center of this circle? @TylerMckinney16
OpenStudy (tylermckinney16):
I am not sure.
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OpenStudy (ijlal):
look at your attachment carefully i say it is (0,-5) where a would be 0 and b would be -5 do you agree?
OpenStudy (tylermckinney16):
Yes
OpenStudy (ijlal):
so put the center coordinate that is (0,-5) in the equation of the circle above and the radius would be 5 units
OpenStudy (tylermckinney16):
ok
OpenStudy (ijlal):
radius is the distance from the center of the circle to it's circumference or you can say half the diameter so the diameter is 10 radius would be 5
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OpenStudy (ijlal):
\[(x-0)^2+(y+5)^2=5^2\]
OpenStudy (tylermckinney16):
Ok cool.
OpenStudy (ijlal):
so the final equation would be \[x^2+(y+5)^2=25\]
this is your answer :) you can graph it on desmos if you would like to double check
OpenStudy (ijlal):
OpenStudy (tylermckinney16):
Ok thanks :)
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