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Mathematics 19 Online
OpenStudy (tylermckinney16):

Help please.

OpenStudy (tylermckinney16):

Questions here.

OpenStudy (tylermckinney16):

@Directrix

OpenStudy (ijlal):

the equation of a circle is \[(x-a)^2 + (y-b)^2 = r^2\] where (a,b) is the center of the circle and r is the radius(distance between the center to the circumference)

OpenStudy (ijlal):

what do you think is the center of this circle? @TylerMckinney16

OpenStudy (tylermckinney16):

I am not sure.

OpenStudy (ijlal):

look at your attachment carefully i say it is (0,-5) where a would be 0 and b would be -5 do you agree?

OpenStudy (tylermckinney16):

Yes

OpenStudy (ijlal):

so put the center coordinate that is (0,-5) in the equation of the circle above and the radius would be 5 units

OpenStudy (tylermckinney16):

ok

OpenStudy (ijlal):

radius is the distance from the center of the circle to it's circumference or you can say half the diameter so the diameter is 10 radius would be 5

OpenStudy (ijlal):

\[(x-0)^2+(y+5)^2=5^2\]

OpenStudy (tylermckinney16):

Ok cool.

OpenStudy (ijlal):

so the final equation would be \[x^2+(y+5)^2=25\] this is your answer :) you can graph it on desmos if you would like to double check

OpenStudy (ijlal):

OpenStudy (tylermckinney16):

Ok thanks :)

OpenStudy (ijlal):

glad to help :)

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