Question

What are the zeros of the function ?

Answer 1

http://prntscr.com/ayc76y

Answer 2

Quadratic equation when y = 0.

Answer 3

i dont have a graphing calculator

Answer 4

You do not require a graphing calculator.
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 5

49?

Answer 6

the formula that was posted above was the quadratic formula which is one method of finding the zeroes (aka roots) of a quadratic equation.

the roots are basically the two x-values, when inputted into the equation, will result in \(y = 0\) because the standard form of quadratics say \(ax^2 + bx + c = 0\). in other words, every quadratic equation will equal to 0.

I prefer to use the factor by grouping method for this question.

Answer 7

can u show me

Answer 8

so in factor by grouping, what you need to do is

1) multiply the A and C terms of the quadratic
do you know the those two terms?

Answer 9

A=1 B=9 C=4

Answer 10

your A term is incorrect. what is the number in front of x^2?

Answer 11

2* SORRY

Answer 12

correct

Answer 13

so first you need to multiply the A and C terms. what is the product?

Answer 14

8

Answer 15

good

Answer 16

the second step requires for you to find the factors of 8 when added together will give you the B term.

Answer 17

1?

Answer 18

1 and ___?

Answer 19

8 = 9?

Answer 20

if you mean to say 1 and 8 then it's correct because 1 x 8 = 8 and 1 + 8 = 9.

Answer 21

so now expand this quadratic into:
2x^2 + 1x + 8x + 4 = 0

Answer 22

`2x^2 + 1x + 8x + 4 = 0 ` is basically the same thing as 2x^2 + 9x + 4 = 0 because you would just need to combine the like terms (1x + 8x = 9x).

Answer 23

do you understand this so far?

Answer 24

i do so far. but i still dont see the answer

Answer 25

you won't see it just yet.

Answer 26

now this is the part where you would need to "factor by grouping" which is the main point of this method.