Question

Answer Check!! Calculus!! Medal!!

Answer 1

R is the 4th quadrant region enclosed by the x-axis and the curve y = x^2 – 2kx, where k > 0. Find the value of k so that the area of the region R is 36 square units.

2
3 <--
4
6

Answer 2

looks good to me unless i made an error

this is the way I went about it:
calculate intersections of y=0 and y=x^2-2kx
those were my lower and upper limits (the intersections were)
You should find that between these intersections that 0>x^2-2kx for x on that interval
so your upper function is f(x)=0 and your lower function is g(x)=x^2-2kx

did the whole integration and plug in limits and solve the equation for k

Answer 3

that's exactly what i did. Glad we got the same answer :D