Question

Find the vertex, the y-intercept, and the x-intercepts (if any exist,) and the graph the function.
Could someone please see if I'm doing this right?

Answer 1

A quadratic is a function of the form f(x)=ax^2+bx+c, where a, b, and c are real numbers and a=0
for the given function a=1 b=4 and c=3

Answer 2

Not really sure howw to explain but I have the answer for x inters, yinte, and vertex

Answer 3

The vertex occurs at \[x=-\frac{ b }{ 2a }\]. To find the x-corrdinate of the vertex of the given function, substitube the values of a and b into the expression and simplifying

Answer 4

let a = 1 and b = 4
\[x=-\frac{ b }{ 2a }=\frac{ 4 }{ 2(1) }\]

Answer 5

The vertex has an x-cooedinate of 2. To find x-coordinate, we evaluate f(2)
\[f(2)=(2)^2+4(2)+3=-2\]
the vertex is \[(-2, 2)\]

Answer 6

For the first step there's three steps in this problem

Answer 7

You got the vertex wrong. . . you're really close though

Answer 8

you're x is correct but the Y should be shifted down to -1

Answer 9

really? Why would it be -1 tho?

Answer 10

Is it because I didn't put it in fraction form like Leana does?

Answer 11

Ok so since the equation is x^2+4x+3
and the x=-2 you'd plug in -2 like this. . .
-2^2+4(-2)+3
and that would equal 4-8+3 which equals -1
y=-1

Answer 12

Okay so if it's (-2, -1) when we go to if the y-intercpt it would look something like this?
\[f(-1)=(-1)+4(-1)+3\]

Answer 13

Tell me what you get for your answer and I'll let you know if your right or not

Answer 14

But first while you do that I'll get this in factored form

Answer 15

I got this first part right but the second one wrong

Answer 16

\[f(-1)=(-1)^2+4(-1)+3=-1-4x+3?\]

Answer 17

x^2+4x+3
And since 3+1=4 and 3*1=3 factored form will be this
(x+3)(x+1)
Making your X- intercepts -3 and -1

Answer 18

Nope (0,3)

Answer 19

we both got it wrong

Answer 20

? No the x Interceps are -3 and -1 and I know thats right cuz I double checked with a graphing computer

Answer 21

Well that's what Mathxl says it is

Answer 22

Well I guess will have to open a new question. . .

Answer 23

you typed in the yinter there so I wasn't wrong thank god

Answer 24

what do you mean I did not

Answer 25

The top ones right the second ones wrong

Answer 26

Whatever I'm done with Mathxl

Answer 27

No, no, no

Answer 28

Yes how long I've been working on this? And Leana can't even get 3 right and she's done that one like three or four times already

Answer 29

I'll do it I'm logging in it now

Answer 30

no don't do that

Answer 31

*Sigh* you need to do yours not mine

Answer 32

Ok. . .

Answer 33

I've got a new problem

Answer 34

k open the problem so I can see it

Answer 35

K