Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
\[-6^4y^5-15x^3y^2+9x^2y^3\]
OpenStudy (irish_waffl3):
Idk how to medal, but I will if you tell me how
OpenStudy (welshfella):
look for the GCF (greatest common factor) for the 3 terms
OpenStudy (cas_fangirl_14):
Do you want step by step instructions or just the answer?
OpenStudy (irish_waffl3):
both
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
first look ate the 3 numbers -6 , -15 and 9 - what number will divide into each of theses?
OpenStudy (irish_waffl3):
3
OpenStudy (welshfella):
No direct answers please
OpenStudy (irish_waffl3):
three is the number that will divide evenly into the three numbers.
OpenStudy (welshfella):
yes now look at the x terms
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
-15x, and 9x?
OpenStudy (welshfella):
is there an 'x' in each term?
OpenStudy (irish_waffl3):
yes all three, nevermind
OpenStudy (irish_waffl3):
6x, 9x, and -15x
OpenStudy (welshfella):
is there a mistake in the first term should it be 6x^4y^5 ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
yes
OpenStudy (irish_waffl3):
sorry
OpenStudy (irish_waffl3):
\[-6x^4y^5-15x^3y^2+9x^2y^3\]
OpenStudy (welshfella):
OK
so we need the GCF of x^4 , x^3 and x^2
OpenStudy (irish_waffl3):
how do I find that?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
look at the lowest, x^2 - will it divide into x^3 and x^4?
OpenStudy (irish_waffl3):
yes
OpenStudy (irish_waffl3):
i think
OpenStudy (welshfella):
so thats your GCF
now what about the terms in y?
OpenStudy (irish_waffl3):
how do I divide the x terms
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
im sorry, im lost
OpenStudy (irish_waffl3):
in alg
OpenStudy (irish_waffl3):
good help though
OpenStudy (welshfella):
x^3 / x^2 = x^(3-2) = x
x^4 / x^2 = x^(4-2) = x^2
- one of the laws of indices.
OpenStudy (irish_waffl3):
ok, how long does it usually take to solve?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
not long once you know the basic rules
OpenStudy (irish_waffl3):
ok
OpenStudy (welshfella):
so for y^5 , y^2 and y^3 the GCF is y^2
so GCF of the whole expression is
3x^2y^2
now you divide this into the 3 terms - the result goes into parentheses
OpenStudy (irish_waffl3):
ok, 3x^2y^2
OpenStudy (irish_waffl3):
why 3x
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
3x^2 - because 3 is gcf of numbers and x^2 is gcf of the x terms
OpenStudy (irish_waffl3):
ok
OpenStudy (welshfella):
and y6 is gcf for y terms
OpenStudy (irish_waffl3):
ok
OpenStudy (irish_waffl3):
so it would be 3x^2y^6 ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
so first divide -6x^4y^5 by 3x^2y^2 we get -2x^2y^3
OpenStudy (irish_waffl3):
ok
OpenStudy (welshfella):
no its y^2 because thats the gcf of the y terms
OpenStudy (welshfella):
so we have
3x^2y^2 ( -2 x^2y^3 )
and there are 2 more terms to go into the parentheses
OpenStudy (irish_waffl3):
ok
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
the second one is -15 x^3 y^2 / 3 x^2 y^2
what does that come to . Try to do the division.
OpenStudy (irish_waffl3):
ok
OpenStudy (welshfella):
first part is -15 ? 3 = -5
OpenStudy (welshfella):
* -15 / 3 = -5
OpenStudy (irish_waffl3):
so-5
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
sorry, i went to get a pen
OpenStudy (welshfella):
right now x^3 / x^2 ?
OpenStudy (irish_waffl3):
x^6 ?
OpenStudy (irish_waffl3):
x^1.5
OpenStudy (irish_waffl3):
not possible
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
idk
OpenStudy (welshfella):
No you are DIVIDING so you SUBTRACT the exponents
x^3 / x^2 = x^(3-2) = x^1 = x
OpenStudy (irish_waffl3):
oh! when you divide variables, you subtract exponents?
OpenStudy (welshfella):
yes
and when yo MULTIPLY variables you ADD exponents
OpenStudy (irish_waffl3):
ok!!! thanks!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
y^2 / y^2 is 1 of course because when you divide something by itse;f anwser is always 1
OpenStudy (irish_waffl3):
correct
OpenStudy (welshfella):
so the second term in the parentheses is -5x
OpenStudy (irish_waffl3):
ok
OpenStudy (irish_waffl3):
so 2x^2y^3+5x?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
so we have
3x^2y^2 ( -2 x^2y^3 - 5x )
OpenStudy (irish_waffl3):
ok
OpenStudy (welshfella):
try and get the third term its + 9x^2y^3 / 3x^2y^2
OpenStudy (welshfella):
9 / 3 =
x^2 / x^2 =
y^3 / y^2 =
OpenStudy (irish_waffl3):
9/3 is 3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
x^2/x^2 is x
OpenStudy (irish_waffl3):
no its 0
OpenStudy (welshfella):
NO
OpenStudy (welshfella):
its 1
OpenStudy (irish_waffl3):
oh ok
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
so 3, 1, and y
OpenStudy (welshfella):
well you needn't put the 1 .
its + 3y
OpenStudy (irish_waffl3):
ok
OpenStudy (welshfella):
- thats the last term in the parentheses.
OpenStudy (irish_waffl3):
ok
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (irish_waffl3):
thank you! how do I medal?
OpenStudy (welshfella):
so thats it
OpenStudy (welshfella):
press Best Response
OpenStudy (irish_waffl3):
ok, i did! :)
OpenStudy (welshfella):
I like ur name!! lol
Still Need Help?
Join the QuestionCove community and study together with friends!