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Algebra 20 Online
OpenStudy (kimberlyevens):

help please

OpenStudy (kimberlyevens):

OpenStudy (kimberlyevens):

@jhonyy9

jhonyy9 (jhonyy9):

2x^2 +2x -2 = 0 so what you see there common in every 3 terms ?

OpenStudy (kimberlyevens):

Um there is a 2

jhonyy9 (jhonyy9):

yes so factoriz out the 2 and so what will get ?

OpenStudy (kimberlyevens):

factorize out the 2?

jhonyy9 (jhonyy9):

yes from every 3 terms and so what will get ?

jhonyy9 (jhonyy9):

2(---)=0

jhonyy9 (jhonyy9):

what will be inside parantheses ?

jhonyy9 (jhonyy9):

one quadratic - do you can write me this quadratic please ?

jhonyy9 (jhonyy9):

2(x^2 +x -1) =0

OpenStudy (kimberlyevens):

(2x^2 + 2x)

OpenStudy (kimberlyevens):

well i was way off

jhonyy9 (jhonyy9):

not what you wrote than you factoriz out from every 3 terms the 2

jhonyy9 (jhonyy9):

so now you need to solve this quadratic - do you know it how ?

OpenStudy (kimberlyevens):

no

jhonyy9 (jhonyy9):

using discriminant

jhonyy9 (jhonyy9):

x^2 +x -1=0 what is formula of discriminant ?

jhonyy9 (jhonyy9):

D = b^2 -4ac so D in this case how many will be ?

jhonyy9 (jhonyy9):

are you here ?

jhonyy9 (jhonyy9):

D = 1 -4(1)(-1) = ?

jhonyy9 (jhonyy9):

b^2 =1

jhonyy9 (jhonyy9):

D = 1+4= ?

OpenStudy (anonymous):

answer is the second one

OpenStudy (t__prodigy):

The answer is b

OpenStudy (t__prodigy):

divide thru by 2. So the equation is x^2 + x -1 = 0. Invariably, a=1, b=1, c=-1 Using the general formular -b + sqrt(b^2-4ac)/2a or -b-sqrt(b^2-4ac)/2a

OpenStudy (t__prodigy):

substitute the values of a b and c...then you are good to go

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