What are the zeros of the function h(x) = x³ – x + 6?

Question

welshfella · Answer

thers no standard way to solve cubic equations but   as 2^3 = 8  what do you think one zero will be?

welshfella · Answer

oh sorry   i should have said  (-2)^3 = -8

try replacing x by -2 in the equation and see what you get

welshfella · Answer

(-2)^2 - (-2) + 6 
- what does that work out to?

welshfella · Answer

if that works out to 0 if you have found  one zero (-2)

radar · Answer

Factor the cubic getting (x+2)(x^2 - 2x + 3) set to 0
now each factor can be solved, note that one zero is as welshfella said, -2
you need to solve the quadratic factor x^2 -2x + 3 = 0.  This will solve the other 2 complex zeros