Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

The options are:
y = one divided by twenty eightx2
x = one divided by twenty eighty2
-28y = x2
y2 = 14x

Question

Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

The options are:
y = one divided by twenty eightx2
 x = one divided by twenty eighty2
 -28y = x2
 y2 = 14x

photon336 · Answer

here is my idea. 

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 (x-h)^2 = 4p(y-k) 

since the vertex is in between the directrix and the focus I think that it's right at the origin. 0,0 

so yeah we also know that the equation opens up sideways. so I believe that 

it would be in the form y^2 = x  

it's either between y^2 = 14x or x = 1/28 y^2