Question

The function f is defined by f(x)=the sqr root 25-x squared for -5 <(or equal to) x<( or equal to) 5.
Find f'(x)
Write an equation for the line tangent to the graph of f at x=-3.
and 2 other questions

Answer 1

\[f(x)=\sqrt{25-x^2}\]?

Answer 2

That is correct

Answer 3

\[\large \frac{d}{dx}[\sqrt{g(x)}]=\frac{g'(x)}{2\sqrt{g(x)}}\] by the chain rule
in your case \(g(x)=25-x^2\)

Answer 4

so i take the derivative of it and I do that by using the chain rule is what you're saying?

Answer 5

yes

Answer 6

okay does this seem right?