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Mathematics 25 Online
OpenStudy (some.random.cool.kid):

im posting this on math, dont judge.

OpenStudy (some.random.cool.kid):

Which of these pairs of objects exerts the greatest gravitational force on each other? Object 1 and Object 3 Object 4 and Object 3 Object 1 and Object 4 Object 4 and Object 2

OpenStudy (some.random.cool.kid):

OpenStudy (some.random.cool.kid):

@AloneS @AravindG

OpenStudy (some.random.cool.kid):

@triciaal @ShadowLegendX

OpenStudy (some.random.cool.kid):

@jim_thompson5910

OpenStudy (erak):

Assuming all of them have the same mass, 1 and 3 I'm pretty sure based on distance

OpenStudy (some.random.cool.kid):

1 and 3?

OpenStudy (some.random.cool.kid):

cool

OpenStudy (some.random.cool.kid):

thats whta i thought but...

OpenStudy (some.random.cool.kid):

explain it first please becuase it may be a trick question, very well.

OpenStudy (erak):

k so force of gravity between two objects FG = Gm1m2/r^2 <--where G is the gravitational constant and the two m's are assumed to be constant and the same, only r can change As you increase r, or distance between the two centers of the objects, you increase the FG, yes, but it is written as a negative, so actually smaller negative FG is stronger

OpenStudy (some.random.cool.kid):

so farther apart ones are stronger is what im hearing?

OpenStudy (some.random.cool.kid):

or was that to prove that 1 and 3 were correct.

OpenStudy (erak):

As in your value of FG will increase, but since it is negative, it's becoming weaker in a sense. So -100 vs -1000.

OpenStudy (some.random.cool.kid):

ah

jimthompson5910 (jim_thompson5910):

based on the equation @Erak wrote, as r increases, the value of 1/(r^2) decreases So as r gets bigger, the force between the objects F gets smaller That's why the earth exerts more gravity on you than say a distant object like Neptune. Though Neptune does have some pull

jimthompson5910 (jim_thompson5910):

I'm not sure how you're getting FG to be negative though

jimthompson5910 (jim_thompson5910):

Gm1m2/r^2 G is some constant (positive) m1,m2 are the masses (positive) r^2 is always positive even if r was negative (r is some positive distance)

OpenStudy (some.random.cool.kid):

yeah i dont see any negatives in this.

OpenStudy (erak):

oh man I was thinking about another physics formula, sorry, ignore the negatives part

OpenStudy (some.random.cool.kid):

so we going with 1 and 3, just to clarify?

jimthompson5910 (jim_thompson5910):

yes, the closer the two objects are, the more force of gravity between them.

OpenStudy (some.random.cool.kid):

figured, well thanks, always better to check.

RhondaSommer (rhondasommer):

dont forget to close this :D

OpenStudy (erak):

@jim_thompson5910 Right, it's the gravitation potential energy equation that requires it to be negative U = -Gm1m2/r Oops, I swear I'm not crazy, just tired.

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