I need help with the law of Cosine, can someone give me an example problem? It just takes a long time to do and i get lost easily.
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OpenStudy (fortytherapper):
Hmm,
Could you please think of two random numbers and one random angle for me?
OpenStudy (warmfridge):
11, 20, and 50 degrees
OpenStudy (fortytherapper):
So Law of Cosines is:
\[c^2 = a^2+b^2 - 2abcos(C)\]
You gave:
\[a = 11\]\[b = 20\]\[C = 50\]
We're looking for little c (the side of):
Let's first plug in values that we have
OpenStudy (warmfridge):
11\[c ^{2}=11^2+20^{2}-2(11)(20)\cos(50)\]
OpenStudy (warmfridge):
ignore the 11 lol
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OpenStudy (fortytherapper):
That's perfect. Now all we have to do is evaluate:
\[11^2 + 20^2 = ?\]
OpenStudy (warmfridge):
521
OpenStudy (fortytherapper):
\[c^2 = 521 - 2(11)(20)\cos(50)\]
I would next do 2(11)(20)
OpenStudy (warmfridge):
440
OpenStudy (fortytherapper):
Now to find what cos(50) is
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OpenStudy (warmfridge):
.642?
OpenStudy (warmfridge):
feels wrong
OpenStudy (fortytherapper):
No, you're right .643. It's a calculus explanation but yeah lol.
\[c^2 = (521) - (441)(.643)\]
Now we just do some basic math steps
OpenStudy (warmfridge):
237.437
OpenStudy (fortytherapper):
\[c^2 = 237.437\]
So last step to finding c is to root both sides, making it:
\[c = \sqrt{237.437}\]
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OpenStudy (warmfridge):
15.4
OpenStudy (fortytherapper):
Yep! That's the answer to that made up problem xP
OpenStudy (warmfridge):
thanks man
OpenStudy (fortytherapper):
You're welcome! You can use the same steps if they ask for a or b or the angle C