Question

calculus help

Answer 1

Did you delete your last question?

Answer 2

no i closed it bc it was answered.

Answer 3

OS is really slow for me right now. Sorry.

Answer 4

The base of a solid is bounded by y=sqrt(x+1), the x-axis, and the line x=1. The cross sections, taken perpendicular to the x axis, are squares. Find the volume of the solid.

Answer 5

A. 1
B. 2
C. 2.333
D. none of these

Answer 6

@Ineedhelplz @mathmate

Answer 7

The key to solving this is to graph the functions and see what shape the base of you solid is. If you slice vertically through this solid you get a square, so the volume of the solid will be the integral of the square of the height of sqrt(x+1) from the x intercept, to x =1.

Answer 8

Integral from 0 to 1 of sqrt(x+1)^2?

Answer 9

Close! You domain of integration is wrong, but the integrand (sqrt(x+1)^2 is correct. Where does sqrt(x+1) have a zero?

Answer 10

-1?

Answer 11

right! so what will your integral be now?

Answer 12

-1 to 1

Answer 13

I got the answer as 2

Answer 14

Right on!

Answer 15

yay thanks

Answer 16

No problem. Good job!