The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?
Which of the following equations is used in the process of solving this problem?
x 2 - 7x + 70 = 0
x 2 - 7x + 10 = 0
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OpenStudy (kmallette09):
please help
OpenStudy (kmallette09):
dont just give the answer
OpenStudy (skullpatrol):
Any ideas?
OpenStudy (kmallette09):
not really hope u could help
OpenStudy (skullpatrol):
The square of a number is equal to 10 less than 7 times that number.
Let x = a number
$$\Huge x^2 = 7x - 10$$
The square of a number is equal to 10 less than 7 times that number
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OpenStudy (skullpatrol):
Does that^ make sense?
OpenStudy (kmallette09):
can u explain a little better
OpenStudy (skullpatrol):
10 less than 7 times that number.
means 7x — 10
OpenStudy (skullpatrol):
Read it like "10 less, than 7x"
OpenStudy (kmallette09):
so is it is x squared- 7x + 10 = 0
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OpenStudy (skullpatrol):
Nope.
OpenStudy (skullpatrol):
The square of a number is equal to 10 less than 7 times that number.
Let x = a number
$$\Huge x^2 = 7x - 10$$
The square of a number is equal to 10 less than 7 times that number
OpenStudy (kmallette09):
oh ok
OpenStudy (skullpatrol):
Now add 10 to both sides
OpenStudy (skullpatrol):
and subtract 7x from both sides
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OpenStudy (kmallette09):
so 7x+10
OpenStudy (skullpatrol):
Start here
$$\Huge x^2 = 7x - 10$$
OpenStudy (kmallette09):
so is it x 2 - 7x + 70 = 0
OpenStudy (skullpatrol):
Nope.
OpenStudy (kmallette09):
x 2 + 7x - 10 = 0 so then its this right here
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