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Solve for B. A = 3(B + C) B = (A - C)/3 B = (3A - C)/3 B = (A - 3C)/3 ill give a medal!!
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@serenity74
Divide the whole equation by (B+C)
So we get : \[\frac{ A }{ B+C } = \frac{ 3(B+C) }{ B+C }\]
The RHS is 3 , right?
yeah
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whats RHS..?
So we get: \[\frac{ A }{ B+C } = 3\]
We'll start again,okay?
ok
This time we divide the whole equation by 3. \[\frac{ A }{ 3 } = \frac{ 3(B+C) }{ 3}\]
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That gives \[\frac{ A }{ 3 } = B+C\]
Move C to the other side.
okay
\[\frac{ A }{ 3 } - C = B\]
Solve the above equation.
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\[\frac{ A - 3C }{ 3 } = B\]
thankyouu
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