Question

Solve for t using logs with base a

Answer 1

\[K=H-Ca^t\]

Answer 2

I'm stuck on what to do on this part
\[K-H=-Ca^t\]

Answer 3

Ca^t = H-K like a first step

Answer 4

k is negative?

Answer 5

divide both sides by C

yes bc. from the left side was added to right side

Answer 6

a^t = (H-K)/C

Answer 7

oh ok yea then it would be loga (h-k)/c=t?

Answer 8

make on the both sides log base a and will get what ?

Answer 9

im not sure what u mean srry

Answer 10

make what?

Answer 11

logarithm base a to the both sides

Answer 12

loga a^t = loga (H-K)/C

Answer 13

hm ok is that the final answer then? i thought u just converted it to a log at that point solving for t

Answer 14

hope you know that

loga a =1

yes ?

Answer 15

no im sorry, am i suppose to use that property here?

Answer 16

yes bc you need to solve it for t - yes ?

so hence using this you get

loga a^t = loga (H-K)/C

tloga a = loga (H-K)/C

t = loga (H-K)/C

Answer 17

oh ok that makes sense. i guess i should go back and take a look at the properties again. thank you so much for explaining it to me. :D

Answer 18

np

was my pleasure

Answer 19

good luck