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OpenStudy (rulerlol113):
Express 3a 2b -1 with positive exponents. this is annoying i dont understand please help me
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OpenStudy (sleepyjess):
Hello ^_^ Welcome to OpenStudy! Could you type the equation using the Equation Editor button?
OpenStudy (rulerlol113):
\[Express 3a ^{2} b ^{-1} with positive exponents.\]
pooja195 (pooja195):
\[\huge~\rm~\bf~3a^2b^{-1}\]
OpenStudy (rulerlol113):
i need to know how to make that positive it shows a fraction as the answer or maybe its a divison thing
pooja195 (pooja195):
@sleepyjess You may continue helping, I wrote out the problem with the equation tool
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OpenStudy (sleepyjess):
Anything with a negative exponent is 1/term^exponent. So if we had \(b^{-8}\), that would turn in to \(\dfrac{1}{b^8}\)
OpenStudy (rulerlol113):
thank you sleepyjess
OpenStudy (sleepyjess):
Here, we have \(b^{-1}\), so what do you think that becomes?
OpenStudy (rulerlol113):
\[\frac{ 1 }{ b ^{1} }\]
OpenStudy (sleepyjess):
Yep :)
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OpenStudy (rulerlol113):
what about the rest?
OpenStudy (sleepyjess):
And then we just plug that back into the equation, which becomes \(3a^2(\dfrac 1b)\), which can actually be further simplified to \(\dfrac{3a^2}{b}\)
OpenStudy (rulerlol113):
thank you so much
OpenStudy (sleepyjess):
No problem :)
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