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Mathematics 20 Online
OpenStudy (watermelon14):

f(x)=x^2-5 and g(x)=6x, then g(f(x)) is equal to i know the answer is 6x^2-30 but i don't know how.

OpenStudy (watermelon14):

@ikram002p ?

hero (hero):

Well, let's see: \(\begin{align*}g(f(x)) &= 6(f(x)) \\&=6(x^2 - 5) \\&=6x^2 - 30\end{align*} \)

OpenStudy (watermelon14):

oh but for g why is it not 6x

hero (hero):

You were given: \(g(x) = 6x\) In the next step, you replace \(x\) with \(f(x)\) to get this: \(g(f(x)) = 6(f(x))\)

hero (hero):

And so that particular step is called "substitution".

jhonyy9 (jhonyy9):

@watermelon14 you dont understand it ?

OpenStudy (watermelon14):

no i understand it but it is a bit confusing still why the x goes away

jhonyy9 (jhonyy9):

where and what x goes ?

hero (hero):

Because they asked you to find \(g(f(x))\). If you notice, when you substitute \(x\) with \(g(x)\) the result is \(g(f(x))\). And only at that point are you able to find the appropriate expression.

hero (hero):

If they asked you to find \(g(6)\) how would you find it? You would have to replace the \(x\) with \(6\).

OpenStudy (watermelon14):

ohh yes now i see. thanks!

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