How can I solve this without using calculator? x=(10^-2.88)²/0.1
Need help?
Yes, please.
Did you right the question wrong tho?
did I write the question wrong? No. It's right...
Just double check
ok!
If it's 10^-2.88
I came this far: x=10^-4,76. But I need to get to 1,7x10^-5
Can you screenshot it? :)
Just a sec
you can write -4.76 as -5+.24 (in sorry I can't bring myself to use a comma for the decimal point for some reason but I know what you mean by the comma ) so you will need to show 10^(.24) is approximately 1.7
Oh, @freckles that's alright...my mistake. In my country we use comma for the decimal...I forgot to change
yea i know it is like that in some countries :p it is cool
@freckles how can I show that?
First thing is first, by PEMDAS, 10^-2.88 is 1/(10^2.88) is 1/(10^2^(1.44)) is one way to look at it.. The other way is 1/(10^2.88) is 1/(10^2*10^.88) either way you need to have good knowledge of the graph of y=10^x or log base 10 of .88 or 1.44
@daniel.ohearn1 so I can't solve this without a graph or calculator?
You can but it's tricky. log base 10 of 1.44 is ln(1.44) / ln(10) somewhere you need to be like okay, I give a good estimate of this value just using my mind.
@daniel.ohearn1 well, thanks. It's part of a question about ionic equilibrium, so... I think I'm gonna use calculator. Thank you.
if you can answer what power must e be taken to get 1.44
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