Question

The general form of the equation of a circle is x2 + y2 + 8x + 22y + 37 = 0.
The equation of this circle in standard form is

HELP WILL MEDAL

Answer 1

The standard form equation of a circle is a way to express the definition of a circle on the coordinate plane.h and k are the x and y coordinates of the center of the circle
so the standard form formula is: (h+k)^2+(y-k)^2=r^2
so your answer is:
(x+y)^2+(8x+22y)+37 = 0

Answer 2

thanks :)))

Answer 3

The standard form of the equation of a circle is

\((x - h)^2 + (y - k)^2 = r^2\)

where point \((h, k)\) is the center of the circle, and \(r\) is the radius.

To get your equation in that form, you need to complete the square for both x and y:

\(x^2 + y^2 + 8x + 22y + 37 = 0\)

\(x^2 + 8x + y^2 + 22y = - 37\)

\(x^2 + 8x + 16 + y^2 + 22y + 121 = - 37 + 16 + 121\)

\((x + 4)^2 + (y + 11)^2 = 100\)

\((x + 4)^2 + (y + 11)^2 = 10^2\)