Please help :) You can make a solar hot dog cooker using foil-lined cardboard shaped as a parabolic trough. The drawing at the right shows how to suspend a hot dog with a wire through the focus of each end piece. If the trough is 12 inches wide and 4 inches deep, how far from the bottom should the wire be placed?
well, to be fair, I'd much rather use a stove for that :)
have you covered parabolas yet?
haha for sure. and yes
does \(\begin{array}{llll} (y-{\color{blue}{ k}})^2=4{\color{purple}{ p}}(x-{\color{brown}{ h}}) \\ (x-{\color{brown}{ h}})^2=4{\color{purple}{ p}}(y-{\color{blue}{ k}})\\ \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\\ {\color{purple}{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\) ring a bell?
no, we learned the formulas y^2=4px and x^2=4py
well ahemm \(\begin{array}{llll} (y-{\color{blue}{ 0}})^2=4{\color{purple}{ p}}(x-{\color{brown}{ 0}})\implies y^2=4px \\ (x-{\color{brown}{ 0}})^2=4{\color{purple}{ p}}(y-{\color{blue}{ 0}})\implies x^2=4py\\ \end{array}\) so, it's pretty much the same thing, but the one you showed above, it's just when h = 0 and k =0, namely, when the vertex is at the origin
but when the vertex is not at the origin, the one shown above, applies, since it's the general form anyhow, putting that aside you're pretty much asked, where the "focus" point for the parabola is at and the focus point is "p" distance from the vertex well, let's take a peek at that cooker |dw:1465258858597:dw| so... the "p" distance, is somewhere between 0 and 4 over the y-axis
Join our real-time social learning platform and learn together with your friends!