Mathematics
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OpenStudy (scarlettfarra2000):
Could someone please see if I'm correct? Question below
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OpenStudy (scarlettfarra2000):
OpenStudy (math&ing001):
It's 4/5 less than 4x..
OpenStudy (scarlettfarra2000):
So we're subtracting?
OpenStudy (math&ing001):
Yep !
OpenStudy (scarlettfarra2000):
\[4x-\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }\]
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OpenStudy (math&ing001):
Yeah, correct
OpenStudy (scarlettfarra2000):
\[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
to find our answer right?
OpenStudy (math&ing001):
Yeah, go on
OpenStudy (scarlettfarra2000):
I don't know how to do the next part
OpenStudy (math&ing001):
\[2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }=2+\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
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OpenStudy (scarlettfarra2000):
So it'd be \[2+5?\] or \[2+\frac{ 5 }{ 10 }\]
OpenStudy (math&ing001):
It's neither. I don't know how you got those...
OpenStudy (scarlettfarra2000):
I just left the two and added \[\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
OpenStudy (math&ing001):
Because they have the same denominator :
\[\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }=\frac{ 1+4 }{ 5 }=\frac{ 5 }{ 5 }=1\]
OpenStudy (scarlettfarra2000):
Okay so 1 is our x?
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OpenStudy (math&ing001):
No, you keep on solving from here \[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
OpenStudy (scarlettfarra2000):
Okay how would I do the next step?
OpenStudy (math&ing001):
\[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2+\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]\[4x=2+1\]This is what we did so far, can't you go from here ?
OpenStudy (scarlettfarra2000):
yes thank you so much for your help
OpenStudy (math&ing001):
Anytime :)