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Mathematics 8 Online
OpenStudy (scarlettfarra2000):

Could someone please see if I'm correct? Question below

OpenStudy (scarlettfarra2000):

OpenStudy (math&ing001):

It's 4/5 less than 4x..

OpenStudy (scarlettfarra2000):

So we're subtracting?

OpenStudy (math&ing001):

Yep !

OpenStudy (scarlettfarra2000):

\[4x-\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }\]

OpenStudy (math&ing001):

Yeah, correct

OpenStudy (scarlettfarra2000):

\[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\] to find our answer right?

OpenStudy (math&ing001):

Yeah, go on

OpenStudy (scarlettfarra2000):

I don't know how to do the next part

OpenStudy (math&ing001):

\[2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }=2+\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]

OpenStudy (scarlettfarra2000):

So it'd be \[2+5?\] or \[2+\frac{ 5 }{ 10 }\]

OpenStudy (math&ing001):

It's neither. I don't know how you got those...

OpenStudy (scarlettfarra2000):

I just left the two and added \[\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]

OpenStudy (math&ing001):

Because they have the same denominator : \[\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }=\frac{ 1+4 }{ 5 }=\frac{ 5 }{ 5 }=1\]

OpenStudy (scarlettfarra2000):

Okay so 1 is our x?

OpenStudy (math&ing001):

No, you keep on solving from here \[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]

OpenStudy (scarlettfarra2000):

Okay how would I do the next step?

OpenStudy (math&ing001):

\[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2+\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]\[4x=2+1\]This is what we did so far, can't you go from here ?

OpenStudy (scarlettfarra2000):

yes thank you so much for your help

OpenStudy (math&ing001):

Anytime :)

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