Could someone please see if I'm correct? Question below
It's 4/5 less than 4x..
So we're subtracting?
Yep !
\[4x-\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }\]
Yeah, correct
\[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\] to find our answer right?
Yeah, go on
I don't know how to do the next part
\[2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }=2+\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
So it'd be \[2+5?\] or \[2+\frac{ 5 }{ 10 }\]
It's neither. I don't know how you got those...
I just left the two and added \[\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
Because they have the same denominator : \[\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }=\frac{ 1+4 }{ 5 }=\frac{ 5 }{ 5 }=1\]
Okay so 1 is our x?
No, you keep on solving from here \[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]
Okay how would I do the next step?
\[4x-\frac{ 4 }{ 5 }+\frac{ 4 }{ 5 }=2+\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 }\]\[4x=2+1\]This is what we did so far, can't you go from here ?
yes thank you so much for your help
Anytime :)
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