Find the derivative of f(x) = 6 divided by x at x = -2.
Hey Josh, welcome to OpenStudy! Recall that we have a handy exponent rule to help us out on problems like this, \(\large\rm \dfrac{1}{x}=x^{-1}\) From there we can apply our `power rule`. Have you learned about power rule yet? Or do we need to use the limit definition of the derivative at this point?
no i havent
I want to say the answer is -3/2 but im not sure if its correct
Ok so we'll have some tricky algebra to take care of then.\[\large\rm f(\color{orangered}{x})=\frac{6}{\color{orangered}{x}}\] If we evaluate this function at x+h, instead of x, it looks like this\[\large\rm f(\color{orangered}{x+h})=\frac{6}{\color{orangered}{x+h}}\]
\[\large\rm \lim_{h\to0}\frac{f(x+h)-f(x)}{h}\quad=\quad \lim_{h\to0}\frac{\frac{6}{x+h}-\frac{6}{x}}{h}\]
so then its not negative its just 3/2
I dunno, you're jumping straight to the end lol :)
so what numbers do i input
\[\large\rm f'(-2)\quad=\quad \lim_{h\to0}\frac{\frac{6}{-2+h}-\frac{6}{-2}}{h}\]I guess -2 is our input. You'll want to do something with the numerator, maybe common denominator, ya?
i dont know how to do that
The derivative of 1/x is -1/x squared Multiply by the constant 6 and you havevthe general derivative. Then replace the x by -2
ohhhh okay! give me a second
so (-1/-2) * 6
Yeah but the -2 is squared
you cant have exponents on the bottom though?
Yes you can If you have exponent -2 for example on top, you can transfer it to the bottom but it becomes 2. The sign of the exponent changes but you can have them both on top or bottom
so the answer is 6!
The answer is 6 *(-1/(-2)squared)
So -6/4
So -3/2
awesome thank you!
So your first answer was correct
You're welcome :)
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