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Mathematics 19 Online
OpenStudy (niuuu):

I just don't get Logs oh well can someone explain this to me

jhonyy9 (jhonyy9):

what you like to know about logarithms ?

OpenStudy (niuuu):

well wait a second it wont let me post the graph

OpenStudy (niuuu):

@jhonyy9

OpenStudy (niuuu):

incase anyone wants to know I think its A but suggestions if I'm wrong would be greatly appreciated

OpenStudy (mjdennis):

Are you willing to tackle this from the beginning?

OpenStudy (mjdennis):

OpenStudy (mjdennis):

That's the plot of y=ln(x) courtesy wikipedia

OpenStudy (niuuu):

@mjdennis yes I am

OpenStudy (mjdennis):

Notice two things - the vertical asymptote is x=0. (x cannot be less than zero, and for x close to zero, y is large and negative.)

OpenStudy (mjdennis):

And at x=1, y= 0.

OpenStudy (mjdennis):

Now, two choices. You can now solve this without ever needing to know more about logarithms, or we can talk about logarithms. I think the first choice. Do you want to choose.

OpenStudy (mjdennis):

I'm going to start my choice while you think about it. In the graph for your problem, what is the lowest value of x?

OpenStudy (mjdennis):

For sure, it isn't 0. But the graph of ln(x) has 0 as the lower limit for x. So we have to use ln(x+a) or ln(x-a) to shift the ln(x) graph to a new place.

OpenStudy (mjdennis):

I will be away fro a minute or two, while you start those answers.

OpenStudy (niuuu):

@mjdennis I got D after I saw which ones shifted and where they shifted too

OpenStudy (mjdennis):

Good catch, that's the one.

OpenStudy (niuuu):

@mjdennis thank you so much

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