just another step by step if you take your time with me youll find it worth it<3
Length of the conjugate axis is the value of b in this case.
Since the equation of the ellipse is of the form: \[\frac{ x ^{2} }{ a ^{2} }-\frac{ y ^{2} }{ b ^{2} }=-1\]
So can you find b now?
@prathamesh_M is b=144 or is it 12
Heyy
@ganeshie8 hi how are you
a squared is 144 and b squared is 16.
@prathamesh_m so b=8 then
anyone?
I've actually never heard of conjugate axis :) lol looking it up
ooh thank you XD
This much should be true : The length of conjugate axis is either 2*4 or 2*12
Transverse axis – contains the vertices as endpoints Conjugate axis – contains the co-vertices as endpoints
\[\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1\] Conjugate axis = \(2b\)
Hey what's up, I noticed you bumped your question, did you get it?
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