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Mathematics 18 Online
OpenStudy (niuuu):

just another step by step if you take your time with me youll find it worth it<3

OpenStudy (niuuu):

OpenStudy (prathamesh_m):

Length of the conjugate axis is the value of b in this case.

OpenStudy (prathamesh_m):

Since the equation of the ellipse is of the form: \[\frac{ x ^{2} }{ a ^{2} }-\frac{ y ^{2} }{ b ^{2} }=-1\]

OpenStudy (prathamesh_m):

So can you find b now?

OpenStudy (niuuu):

@prathamesh_M is b=144 or is it 12

ganeshie8 (ganeshie8):

Heyy

OpenStudy (niuuu):

@ganeshie8 hi how are you

OpenStudy (prathamesh_m):

a squared is 144 and b squared is 16.

OpenStudy (niuuu):

@prathamesh_m so b=8 then

OpenStudy (niuuu):

anyone?

zepdrix (zepdrix):

I've actually never heard of conjugate axis :) lol looking it up

OpenStudy (niuuu):

ooh thank you XD

ganeshie8 (ganeshie8):

This much should be true : The length of conjugate axis is either 2*4 or 2*12

ganeshie8 (ganeshie8):

Transverse axis – contains the vertices as endpoints Conjugate axis – contains the co-vertices as endpoints

ganeshie8 (ganeshie8):

ganeshie8 (ganeshie8):

\[\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1\] Conjugate axis = \(2b\)

OpenStudy (astrophysics):

Hey what's up, I noticed you bumped your question, did you get it?

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