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OpenStudy (niuuu):
just another step by step if you take your time with me youll find it worth it<3
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OpenStudy (niuuu):
OpenStudy (prathamesh_m):
Length of the conjugate axis is the value of b in this case.
OpenStudy (prathamesh_m):
Since the equation of the ellipse is of the form:
\[\frac{ x ^{2} }{ a ^{2} }-\frac{ y ^{2} }{ b ^{2} }=-1\]
OpenStudy (prathamesh_m):
So can you find b now?
OpenStudy (niuuu):
@prathamesh_M is b=144 or is it 12
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ganeshie8 (ganeshie8):
Heyy
OpenStudy (niuuu):
@ganeshie8 hi how are you
OpenStudy (prathamesh_m):
a squared is 144 and b squared is 16.
OpenStudy (niuuu):
@prathamesh_m so b=8 then
OpenStudy (niuuu):
anyone?
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zepdrix (zepdrix):
I've actually never heard of conjugate axis :) lol
looking it up
OpenStudy (niuuu):
ooh thank you XD
ganeshie8 (ganeshie8):
This much should be true :
The length of conjugate axis is either 2*4 or 2*12
ganeshie8 (ganeshie8):
Transverse axis – contains the vertices as endpoints
Conjugate axis – contains the co-vertices as endpoints
ganeshie8 (ganeshie8):
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ganeshie8 (ganeshie8):
\[\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1\]
Conjugate axis = \(2b\)
OpenStudy (astrophysics):
Hey what's up, I noticed you bumped your question, did you get it?
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