Question

State whether the given measurements determine zero, one, or two triangles.

B = 86°, b = 21, c = 18

Answer 1

42

Answer 2

actually
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Answer 3

@AceSpeedFighter
Wow, can't break that code.

Answer 4

its easy 23432x312312x0-e3i=-23i0-x0i03ii-0ix9ixiu90ux01u3=-1x04=0=x1 ]

Answer 5

ok then I would use the law of sines?

Answer 6

Would it be two triangles?

Answer 7

yes

Answer 8

no

Answer 9

65+42 is like 21

Answer 10

@mathstudent55 @mathmate ??

Answer 11

so divide it by 10 and 9

Answer 12

you get 8

Answer 13

so its siple

Answer 14

Times it by the times =you said hello

Answer 15

Use the law of sines to find C.
Then use the law of sines again to find a

Answer 16

b/sinB = c/sinC (sine law)
21/sin86° = 18/sinC
sinC = sin86° × (18/21)
C = 58.8° or C = 180° - 58.8°
C = 58.8° or C = 121.2° (rejected for B + C = 207.2° > 180°)

Answer 17

right?

Answer 18

Yes, well-done! :)

Answer 19

so two or one triangles?

Answer 20

How many solutions do you have for sin C? That would correspond to the number of possible triangles.

Answer 21

I think 2

Answer 22

Correct.
We have an angle of 86 deg.
Angle C is 58.8 or 121.2, but 121.2 is too large bec of angle of 86 deg.
That means angle C can have only 1 measure, 58.8, and there is only 1 triangle.

Answer 23

:) Thank you!

Answer 24

yw

Answer 25

Can you help with another?

Answer 26

Solve the triangle.

A = 19°, C = 102°, c = 6

Answer 27

Use the sine rule,
sin C/c = sin A /a
and find a.
Since one of the angles is obtuse, the two remaining angles must be acute, and hence only one possible solution.