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Mathematics 20 Online
zarkam21 (zarkam21):

Help please

OpenStudy (redstonemak3r):

sure

OpenStudy (redstonemak3r):

ill try

zarkam21 (zarkam21):

OpenStudy (redstonemak3r):

do you think you can write it down

zarkam21 (zarkam21):

@agent0smith

OpenStudy (redstonemak3r):

@SQL_Server

OpenStudy (agent0smith):

\[\large SA = 4\pi r^2\]There is 2 ways to do this: Method 1) use the SA formula to find the r of the small sphere. Then find the SA of the big one. Method 2) use the fact that since SA depends on r^2, when you *double* the radius from r to 2r, you *quadruple* the SA.

zarkam21 (zarkam21):

The small one is \[8100\]

OpenStudy (agent0smith):

The small what? The r for the small cannot be that large. Method 2 is easier btw.

zarkam21 (zarkam21):

i got 8100pi

OpenStudy (agent0smith):

Notice you were given the SA for the small, NOT the radius.

zarkam21 (zarkam21):

i did \[SA=(4)( \pi )(45)^{2}\]

OpenStudy (agent0smith):

See last post

zarkam21 (zarkam21):

well would it be 45*2 then

OpenStudy (agent0smith):

\[45=(4)( \pi )r^{2}\]solve for r

zarkam21 (zarkam21):

1.89

OpenStudy (agent0smith):

Looks right Now find the SA for the big one. You know the radius is 2 times the small one.

zarkam21 (zarkam21):

the SA formula right

OpenStudy (agent0smith):

Yes

zarkam21 (zarkam21):

179.55

OpenStudy (agent0smith):

you could keep it exact using Method 2) use the fact that since SA depends on r^2, when you *double* the radius from r to 2r, you *quadruple* the SA. Old SA was 45, new SA will be 4*45

zarkam21 (zarkam21):

So A

zarkam21 (zarkam21):

because it would be squared right

OpenStudy (agent0smith):

Correct

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