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OpenStudy (redstonemak3r):
sure
OpenStudy (redstonemak3r):
ill try
zarkam21 (zarkam21):
OpenStudy (redstonemak3r):
do you think you can write it down
zarkam21 (zarkam21):
@agent0smith
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OpenStudy (redstonemak3r):
@SQL_Server
OpenStudy (agent0smith):
\[\large SA = 4\pi r^2\]There is 2 ways to do this:
Method 1) use the SA formula to find the r of the small sphere. Then find the SA of the big one.
Method 2) use the fact that since SA depends on r^2, when you *double* the radius from r to 2r, you *quadruple* the SA.
zarkam21 (zarkam21):
The small one is \[8100\]
OpenStudy (agent0smith):
The small what? The r for the small cannot be that large.
Method 2 is easier btw.
zarkam21 (zarkam21):
i got 8100pi
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OpenStudy (agent0smith):
Notice you were given the SA for the small, NOT the radius.
zarkam21 (zarkam21):
i did \[SA=(4)( \pi )(45)^{2}\]
OpenStudy (agent0smith):
See last post
zarkam21 (zarkam21):
well would it be 45*2 then
OpenStudy (agent0smith):
\[45=(4)( \pi )r^{2}\]solve for r
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zarkam21 (zarkam21):
1.89
OpenStudy (agent0smith):
Looks right
Now find the SA for the big one. You know the radius is 2 times the small one.
zarkam21 (zarkam21):
the SA formula right
OpenStudy (agent0smith):
Yes
zarkam21 (zarkam21):
179.55
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OpenStudy (agent0smith):
you could keep it exact using
Method 2) use the fact that since SA depends on r^2, when you *double* the radius from r to 2r, you *quadruple* the SA.
Old SA was 45, new SA will be 4*45