Question

Hi guys; I need help understanding how sin x times sec x equals opposite over adjacent.
I have no clue (-.-)

Answer 1

Do you know what sin is in terms of opposite, adjacent and hypotenuse?

Also: Hint: \(\large\sf sec ~x = \frac{1}{cos~x}\)

Answer 2

Sine equals opposite over hypotenuse. (Going in the right direction?)

Answer 3

Correct!

Now, what is cos = ?

Answer 4

Cosine equals adjacent over hypotenuse. :D

Answer 5

yup! :D

now, sec x = 1/cos x

so to find sec in those terms, we need to find the reciprical of cos x

the reciprical of a/b is b/a

so what is the recirpocal of adjacent/hypotenuse?

Answer 6

Hypotenuse over adjacent

Answer 7

correct, now

sin x * sec x

let's re-write them in the terms we said:

\(\sf\Large \frac{opposite}{hypotenuse} \times \frac{hypotenuse}{adjacent} =\)

now simplify it :)

Answer 8

opposite times adjacent?
HOLY CRAP I GET IT LOL
Thank you!!!

Answer 9

Yay! Correct!

Now... wait a minute. Did you mean opposite over adjacent? :P

Answer 10

No D:

Answer 11

Oh wait, since they canceled out, can't I put in 1 and then multiply and get opposite over adjacent?

Answer 12

ok, you see:

\(\sf\Large \frac{opposite}{\cancel{hypotenuse}} \times \frac{\cancel{hypotenuse}}{adjacent} =\)

since we have it in the denominator and the numerator

Answer 13

XD Yes. I think I understand now :D

Answer 14

Great! :D

Also, by the way, opposite/adjacent is tan :P

Just something you might want to remember. Never know when it will help.

And tan = sin/cos

That's all! :D

Answer 15

Wow :0
thanks for telling me!