A man looks at the top of a building. He is 3 metres from the base and the building is 20 m tall. Find the distance from his point to the top of the building 'x'.
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OpenStudy (ksmd13):
pooja195 (pooja195):
Hi there!
Any ideas on where to start?
OpenStudy (ksmd13):
not really :/
pooja195 (pooja195):
Here we would use the Pythagorean theorem
Which is
\[\huge~\rm~a^2+b^2=c^2\]
OpenStudy (ksmd13):
ok so x^2 = 20^2 + 3^2?
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pooja195 (pooja195):
Yep now continue to solve
pooja195 (pooja195):
20^2=?
OpenStudy (ksmd13):
I'm not sure how to figure that part out
pooja195 (pooja195):
20^2=20*20=?
OpenStudy (ksmd13):
oh i'm dumb lol 400
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pooja195 (pooja195):
you're not dumb we all learn at different paces :)
Next,3^2=?
OpenStudy (ksmd13):
6
pooja195 (pooja195):
3*3=?
Remember its 3^2
OpenStudy (ksmd13):
oh 9
OpenStudy (ksmd13):
so then it would be 409?
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pooja195 (pooja195):
yep!
Now we have
\[\huge~\rm~x^2=409\]
Any ideas on how to cancel out the square?