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Mathematics 21 Online
OpenStudy (ksmd13):

A man looks at the top of a building. He is 3 metres from the base and the building is 20 m tall. Find the distance from his point to the top of the building 'x'.

OpenStudy (ksmd13):

pooja195 (pooja195):

Hi there! Any ideas on where to start?

OpenStudy (ksmd13):

not really :/

pooja195 (pooja195):

Here we would use the Pythagorean theorem Which is \[\huge~\rm~a^2+b^2=c^2\]

OpenStudy (ksmd13):

ok so x^2 = 20^2 + 3^2?

pooja195 (pooja195):

Yep now continue to solve

pooja195 (pooja195):

20^2=?

OpenStudy (ksmd13):

I'm not sure how to figure that part out

pooja195 (pooja195):

20^2=20*20=?

OpenStudy (ksmd13):

oh i'm dumb lol 400

pooja195 (pooja195):

you're not dumb we all learn at different paces :) Next,3^2=?

OpenStudy (ksmd13):

6

pooja195 (pooja195):

3*3=? Remember its 3^2

OpenStudy (ksmd13):

oh 9

OpenStudy (ksmd13):

so then it would be 409?

pooja195 (pooja195):

yep! Now we have \[\huge~\rm~x^2=409\] Any ideas on how to cancel out the square?

OpenStudy (ksmd13):

do I find the square root?

pooja195 (pooja195):

Perfect :-) \[\huge~\rm~\bf~\sqrt{x^2}=\sqrt{409}\]

OpenStudy (ksmd13):

ok so that would be 20.2237484162

OpenStudy (ksmd13):

tysm for your help! :)

pooja195 (pooja195):

perfect make sure you round that though and your welcome <3

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