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Mathematics 18 Online
ganeshie8 (ganeshie8):

@elusive

ganeshie8 (ganeshie8):

\[\cos(sin^{-1}(1/2)) = ?\]

OpenStudy (elusive):

thats easy

OpenStudy (elusive):

i think

ganeshie8 (ganeshie8):

Haha its made easy on purpose I want you use the triangle method

OpenStudy (elusive):

\[\frac{ \sqrt{3} }{ 2 }\]

ganeshie8 (ganeshie8):

Yep, but no prize to you. You haven't showed steps

OpenStudy (elusive):

I think I got sin, I'll have to study the other functions, now!

OpenStudy (elusive):

|dw:1467919730161:dw|

ganeshie8 (ganeshie8):

Perfect ! Here is your medal

OpenStudy (elusive):

thank you :D

ganeshie8 (ganeshie8):

Wana try another problem ?

OpenStudy (elusive):

Yeah!

ganeshie8 (ganeshie8):

\[\sin(sin^{-1}(2/3)) = ?\]

OpenStudy (elusive):

you can use "arcsin" instead of sin^-1

ganeshie8 (ganeshie8):

I like arcsin too

OpenStudy (elusive):

|dw:1467920041360:dw| I think that was a trick question! it's just 2/3

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