what is the abs val of -4- sq root of 2 i

Question

aaronandyson · Answer

-4-√2i

.sam. · Answer

$$|-4-\sqrt{2}i| \ \ = |-1||4+ \sqrt{2}i|$$
Since $-1\leq 0$, |-1| = 1
$$=|4+\sqrt{2}i|$$
Now use the formula 
$$|z|=|a+bi| = \sqrt{a^2+b^2}$$

aaronandyson · Answer

3√2*i?

.sam. · Answer

Yep, and without the imaginary unit

aaronandyson · Answer

So that 3√2

.sam. · Answer

Mhm

myininaya · Answer

just for fun @AaronAndyson 
you could have pretended the question was what is distance from (-4,-sqrt(2)) to (0,0)
and referred to your old distance formula

$$d=\sqrt{(-4-0)^2+(-\sqrt{2}-0)^2} \ d=\sqrt{(-4)^2+(-\sqrt{2})^2}$$
and then continue simplifying it from here
I hope you can see that the questions are equivalent 
and the formulas sam and I use are equivalent since we are finding a distance between a point given and the origin point

aaronandyson · Answer

Thanks for the suggestion @myininaya

agent0smith · Answer

For future reference, the absolute value of a complex number, refers to its magnitude. You don't need to factor out a -1 as Sam did. All you need is the formula that was given at the end of the post $$\large |z|=|a+bi| = \sqrt{a^2+b^2}$$