Question

How to get a parabola into standard form?

Answer 1

I have the parabola y^2 + 6y - 2x + 13 = 0 that I need to graph. How do I get it into standard form to do so?

Answer 2

This may help you:
http://www.mathwarehouse.com/geometry/parabola/standard-to-vertex-form.php

Answer 3

If it does not please tell me and I'll try my best to assist you.

Answer 4

Ooo completing the square :O fun stuff

Answer 5

Haha why did I get a medal for that XD

Answer 6

Hahaha who gave you a medal?
:)
I'll go check out the link and be back.

Answer 7

k

Answer 8

The undead gave the Honorary Professor of Mathematics a medal because if the link doesn't help you his/her knowledge will.

Answer 9

XD

Answer 10

Hahaha xD

Answer 11

Can one of you guys explain this a little? I'm still stumped

Answer 12

The link was a bit confusing. I did try completing the square...
(y+3)^2 = 2x + 22
But then... I wasn't sure what to do next?

Answer 13

You were ok with the completing the square portion though?
Cause that's really 95% of the problem.

Answer 14

If I did it right, then it was not prob :)

Answer 15

The coefficient looks a little off maybe.. hmm
To complete the square, you needed 9 right?
So you should have taken 9 away from the 13.

Answer 16

The constant term I mean*

Answer 17

I added 9 to both sides :O

Answer 18

Ok good that works also :)
Then subtracting 13 from each side does not give us 22 :OO

Answer 19

9-13 no bueno 22

Answer 20

Oh I thought the 13 was on the other side :P
It should be -4 right?

Answer 21

That posted late lol

Answer 22

\(\large\rm (y+3)^2=2x-4\)
Ok great.
Notice that the square is on the y for this parabola.
So it will open to the left or right,
not the standard up or down that you're used to seeing.

So we need to finish by getting this into the form `x=stuff`.

Answer 23

x=stuff
hmm... what exactly does that entail? ;)

Answer 24

Factor out a 2 maybe?

Answer 25

Hmm well we have subtraction and multiplication.
So solving for x will entail addition and division, ya? :)

Answer 26

4 being subtracted,
2 is multiplying.

Answer 27

Oh we need to solve for x? Lol.
x = (y+3)^2/2 + 2
Look about right?

Answer 28

\[\large\rm x=\frac12(y+3)^2+2\]Ok great!
There is our standard form.

Answer 29

Gracias amigo!

Answer 30

:3

Answer 31

hehe