Which of the following defines a correct relationship for electromagnetic radiation?
a. \(\lambda\alpha v\)
b. \(\lambda\alpha E\)
c. \(E\alpha\frac{1}{v}\)
d. \(v\approx c\)
e. \(v\lambda=c\)
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OpenStudy (kittiwitti1):
the \(\alpha\) is supposed to be this:|dw:1469040501613:dw|
OpenStudy (kittiwitti1):
@mayankdevnani
OpenStudy (mayankdevnani):
what do you think?
OpenStudy (kittiwitti1):
idk, does the \(\alpha\) symbol mean proportional?
OpenStudy (mayankdevnani):
yea
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OpenStudy (kittiwitti1):
ok so uhh
\(\lambda\)=wavelength and \(E\)=?
I think \(v\) is velocity?
OpenStudy (mayankdevnani):
E=energy and v(mue) is frequency
OpenStudy (kittiwitti1):
mue?
ok so
a. wavelength \(\alpha\) energy
b. wavelength \(\alpha\) energy
c. energy \(\alpha\) \(\frac{1}{v}\)
d. frequency \(\approx\) \(c\)
e. frequency * wavelength = \(c\)
also, what is \(c\)?
OpenStudy (mayankdevnani):
|dw:1469041448387:dw|
OpenStudy (mayankdevnani):
c is speed of light
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OpenStudy (kittiwitti1):
ohh, okay o:
so then
\(\color{blue}{\text{Originally Posted}}\)
wavelength \(\alpha\) energy
b. wavelength \(\alpha\) energy
c. energy \(\alpha\) \(\frac{1}{v}\)
d. frequency \(\approx\) light speed
e. frequency * wavelength = light speed
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (mayankdevnani):
what do you think?
any guesses ?
OpenStudy (kittiwitti1):
umm
D and E are wrong because light speed is a set #,
idk anything else though
OpenStudy (mayankdevnani):
E is right
it's a formula
OpenStudy (kittiwitti1):
oh... okay
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OpenStudy (kittiwitti1):
hmm... I think A is right, idk about B, C is maybe
OpenStudy (mayankdevnani):
option A is wrong na
check option E
OpenStudy (kittiwitti1):
but it is a real formula yes? xD
OpenStudy (mayankdevnani):
yea
OpenStudy (mayankdevnani):
so do you agree that option A is wrong ?
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OpenStudy (kittiwitti1):
idk about relationship for electromag radiation lol
OpenStudy (kittiwitti1):
does the radiation have to involve light energy?
OpenStudy (mayankdevnani):
yo
OpenStudy (kittiwitti1):
ohhhh
I see o:
OpenStudy (mayankdevnani):
so option A is incorrect
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OpenStudy (kittiwitti1):
is not relevant to the question basically. o: ?
that means b and c also
OpenStudy (kittiwitti1):
so then (this is from another question);
this is also right??
\(\text{"The speed of light is equal to the product of the wavelength}\)\(\text{and frequency of an electromagnetic wave"}\)
OpenStudy (mayankdevnani):
yea
OpenStudy (mayankdevnani):
smart lady
OpenStudy (kittiwitti1):
hahah ty > <
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OpenStudy (mayankdevnani):
*girl
OpenStudy (kittiwitti1):
aye, am 18, already lady :v
OpenStudy (kittiwitti1):
lol
OpenStudy (mayankdevnani):
lady nuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
OpenStudy (mayankdevnani):
;(
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OpenStudy (kittiwitti1):
hehe
OpenStudy (mayankdevnani):
you're my girl <3
OpenStudy (kittiwitti1):
O_o
OpenStudy (mayankdevnani):
lets back on question,so what are your answers ?
OpenStudy (kittiwitti1):
I answer E o:
also,
this statement \(\text{Electromagnetic radiation travels at a finite speed}\) is it right?
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OpenStudy (mayankdevnani):
E is correct
OpenStudy (mayankdevnani):
yea! correct
OpenStudy (kittiwitti1):
alright! thank you ☺
sorry, I got to go to chem class now ; - ;
OpenStudy (mayankdevnani):
cuz speed of light is a electromagnetic wave and its value is finite
OpenStudy (mayankdevnani):
☺
☺
☺
dun leave me alone
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OpenStudy (mayankdevnani):
pm me
OpenStudy (kittiwitti1):
im sorry ; - ;
OS not for android ; - ;
OpenStudy (kittiwitti1):
byebye </3
OpenStudy (mayankdevnani):
OS is for android as well
use chrome ,you can only pm in mobile