Question

anyone know how to do this?

Answer 1

\[\frac{ x ^{-a} }{ x ^{-b} }=\frac{ x^b }{ x^a }\]

Answer 2

\[\frac{ x^a }{ x^b }=x ^{a-b}\]

Answer 3

@sshayer I am a bit confused

Answer 4

\[4^{-3}=\left( 2^2 \right)^{-3}=2^{-6}\]

Answer 5

let me know where is the difficulty.

Answer 6

so we got 2^-6 what di we do with that?

Answer 7

\[x^a*x^b=x ^{a+b}\]
\[x^a \times x ^{-b}=x ^{a+(-b)}=x ^{a-b}\]

Answer 8

\[2^{-6}\times 2^5=?\]

Answer 9

4^-1

Answer 10

no
\[2^{-6+5}=2^{-1}=\frac{ 1 }{ 2 }\]

Answer 11

oh

Answer 12

now take the case of 5

Answer 13

15^-1

Answer 14

\[\frac{ 5^4 }{ 5^3 }=5^4 \times 5^{-3}=?\]

Answer 15

5^1

Answer 16

=5,correct
now take the case of 3

Answer 17

3^-2

Answer 18

\[\frac{ 1 }{ 3^{-2}\times 3^1 }=3^2\times3^{-1}=?\]

Answer 19

\[3=3^1\]

Answer 20

oh 3 has a one i didnt know that

Answer 21

3^1

Answer 22

\[3^{2-1}=3^1=3\]
correct

Answer 23

so now we have solved in small portions .
Now i will show you to write together.
\[\frac{ 4^{-3} }{ 5^3 }*\frac{ 5^4 }{ 3^{-2} }*\frac{ 2^5 }{ 3 }=4^{-3}*5^{-3}*5^4*3^2*2^5*3^{-1}\]
\[=\left( 2^2 \right)^{-3}*2^{5}*5^{-3+4}*3^{2-1}\]
\[=2^{-6+5}*5^1*3^1=2^{-1}*5*3=\frac{ 5*3 }{ 2 }=\frac{ 15 }{ 2 }\]