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2 ((sin^2)x) = sin x
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subtract sin(x) both sides, what do you get?
2 ((sin^2)x) - sin x = 0
But how would I factor?
pull out the common factor
\[2\sin^2x-\sin x=0,\sin x \left( 2\sin x-1 \right)=0\] either sinx=0 x=? or \[\sin x=\frac{ 1 }{ 2 },find x\]
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Regarding your "2 ((sin^2)x) = sin x" ... I think you probably mean 2 (sin x)^2 = sin x Think about this. What's your conclusion? If you agree with my interpretation, you'll then have \[2 (\sin x)^2=\sin x, \]
or \[2 \sin^2x=\sin x\]
How would you solve that for x?
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