Find all possible numbers, c, so that y={3x-2c if x is less than or equal to 0}{2x^2+x+5c^2 if x>0} is a continuous function
Hi
Hello!
Have you tried anything yet ?
What do you mean?
I'm not sure how to even start the problem.
Me neither, let's read the problem again.
I can draw the equation out
what does it mean for a function to be "continuous" ?
Is below function continuous ? |dw:1471884990839:dw|
No.
why not ?
The graph splits at a number, and it looks as if it has two values for the same place on the graph.
Right, basically we want the function to be smooth
It seems the expression for the function is changing at x = 0 ?
Before x = 0, the expression is 3x-2c after x = 0, the expression is 2x^2+x+5c^2
For the function to be continuous, we want both those expressions to be same at x = 0
plugin x = 0 and set them equal : 3(0) - 2c = 2(0)^2+0+5c^2
see if you can solve "c"
Okay!
I got 0 and -2/5.
looks good http://www.wolframalpha.com/input/?i=solve+3(0)+-+2c+%3D+2(0)%5E2%2B0%2B5c%5E2
Awesome! Thank you!
yw!
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