Question

You are on top of a building that is 75.0 m tall. You toss a ball straight up with an initial velocity of 33.8 m/s. How high does the ball travel? It goes up and then falls down to the ground below. How much time is it in the air?

Answer 1

@jim_thompson5910

Answer 2

the general equation we'll use is
y = -4.9x^2+v*x + h

where...
initial height = h = 75
initial velocity = v = 33.8
x = time
y = height at time x

with me so far?

Answer 3

yes

Answer 4

So
y = -4.9x^2+v*x + h
turns into
y = -4.9x^2+33.8*x + 75

Answer 5

are you able to find the vertex of `y = -4.9x^2+33.8*x + 75` ?

Answer 6

Could I use the formula
x=v^2/2a ?