If a reaction experiences a small decrease in entropy, but also releases a large amount of heat, the reaction will be spontaneous.
True
False
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OpenStudy (jonathan34):
hello
OpenStudy (jonathan34):
It is true...The relevant equation is:
DG = DH - TDS
In order for the reaction to be spontaneous, DeltaG must be less than zero. If Delta S is negative, the -TDS term will be positive. As long as DeltaH is more negative than TDS is positive, the reaction will be spontaneous.
An example of this situation is the freezing of water at temperatures below 0C. The entropy of the water decreases but it is also exothermic (DeltaH < 0).
Hope that helps...
OpenStudy (jonathan34):
wait wrong guy lol to questions at the time
NvidiaIntely (nvidiaintely):
why wrong guy?
OpenStudy (jonathan34):
HEY
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OpenStudy (jonathan34):
ok
OpenStudy (jonathan34):
am ding to ppl at the same time
OpenStudy (jonathan34):
doing
NvidiaIntely (nvidiaintely):
Oh okay.
NvidiaIntely (nvidiaintely):
Let me get @Google
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OpenStudy (jonathan34):
on on openstudy and other on answers
NvidiaIntely (nvidiaintely):
Okay
OpenStudy (google):
I am sort of hung up on this one
NvidiaIntely (nvidiaintely):
okay its fine.
I think its true.
OpenStudy (google):
its not spontaneous because when something has a low amount of entropy it doesnt just let off a lot of heat, im pretty sure its false
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