um can some one help me graph this

Question

um can some one help me graph  this

khsbxckjsb · Answer

f(x)= -2x/3 + 490

mathmale · Answer

This function has the form y=mx+b, the "slope-intercept" form.  Comparing your function f(x)=-2x/3+490 to y=mx+b, please identify the value of the slope, m, and the value of the y-intercept, b.

m=?
b=?

khsbxckjsb · Answer

m would equal 3 and b would equal 490

khsbxckjsb · Answer

sorry m would equal 2

mathmale · Answer

Compare -2x/3 to mx:  Rewrite -2x/3 as (-2/3)x.  Now try again:  What is the slope, m?

khsbxckjsb · Answer

-1.5

mathmale · Answer

In this case, the slope, m, consists of a fraction.

mathmale · Answer

Please show how you got that.    Once again, -2x/3 can be re-written as (-2/3) x.
What is the coefficient of x, and what does it represent?

3mar · Answer

$$f(x)=-2x/3+490 $$
$$f(x)=\frac{ -2 }{ 3 }x+490s$$
Compare that with the slope-intercept form ...$$f(x)=m.x+b$$

Easily you can notice that the slope, m, is equal to $$\frac{ -2 }{ 3 }$$

This is just an illustration of what mathmale wants to represent.

mathmale · Answer

Right.  The slope here is -2/3 or  (-2/3).  Strongly suggest that you use parentheses:  (-2/3).

mathmale · Answer

Now the y-intercept is (0,490).  Plot that on a set of coordinate axes.
Starting at that point, lay out the slope (-2/3).  Suggestion:  From (0,490), move 3 units to the right, and then 2 units down.  Plot a point at your new location.  Draw a straight line thru both points.

3mar · Answer

I am 3mar, not khsbxckjsb.

3mar · Answer

This could help him.