Question

I need help plse will give medal

Answer 1

What do you think the length (horizontal) is?

Answer 2

HINT: they have given you co-ordinates, just use them to get the length

Answer 3

8?

Answer 4

I say 8 cuz it doesn't start directly on 0

Answer 5

Yup

Answer 6

vertical is 6

Answer 7

yup

Answer 8

sqrt(x^2+y^2)

Answer 9

100?

Answer 10

how did you get that?

Answer 11

You forgot to take sqrt fo 100

Answer 12

so 10

Answer 13

oh ok! yeah sorry frgot

Answer 14

now do #5

Answer 15

question 5 is 14

Answer 16

and in 6 I'm guessing I would have to subtract 14-10?

Answer 17

yup

Answer 18

so what would I put for 6 -4 or just 4

Answer 19

for 6) they are asking whether the dist. of hypotenuse is > or < than the dist. of two sides

Answer 20

10<14?

Answer 21

-4 indicates that the distance if we chose to take displacement vector

Answer 22

yes

Answer 23

oh ok! can u help me with another one I have it all done just want someone to chck it

Answer 24

Sure, post the question and answers to it.

Answer 25

4*50 right

Answer 26

x cpt is 9-1=8units, ycpt is 10-4 = 6units
8x8=64, 6x6=36, 64+36=100, square root of 100 = 10 (it's a 3,4,5 triangle scaled up, I think)
distance travelled is xcp plus y cpt = 8+6 = 14 units (in other words, it's taken "the long way round")
14 is bigger than 10, not quite half as much again.
Bon voyage
http://perendis.webs.com

Answer 27

thanks

Answer 28

yeah I did 4*50

Answer 29

would be 200 not 250

Answer 30

o yeah! I miss calculated

Answer 31

how bout the other question would it be like that or would it just be 50+50+50+50?

Answer 32

other is right

Answer 33

-*+=-

Answer 34

ok thank u so much!