Question

eliminate 6x=18-12 y and 7x+4y=9 need both x and y individually I really don't understand how to do it.

Answer 1

they are asking you to find the point of intersection for the 2 linear equations...

it looks like you need to use the elimination method

so take the 1st equation and divide every term by 6... as 6 is a common factor

you get

x = 3 - 2y

for me, the easy method is to use substitution... so you take the equation above and substitute it into

7x + 4y = 9

or

7(3 - 2y) + 4y = 9

distribute and solve for y

can you check the equation about and make sure it is = 9 and not = -9

when you find y, substitute it into either equation to find x.

hope it helps

Answer 2

you could also graph the two lines and look at the point they intersect.

Answer 3

Or you can try the elimination method:
6x=18-12 y
7x+4y=9
Let's rearrange the 1st equation

a) 6x +12y=18
b) 7x+4y=9

Multiply equation "b" by -3
a) 6x +12y=18
b) -21x -12y=-27

Adding both equations:
-15x = -9
x = .6
and now you can easily solve for y

Answer 4

"eliminate 6x=18-12 y and 7x+4y=9 need both x and y individually" would be better written as "Solve the system of linear equations 6x=18-12y and 7x+4y=9 for x and y through elimination." In other words, eliminate one variable (by addition / subtraction or substitution, find the value of the other variable, and then use one of the above equations to find the 2nd unknown variable.