eliminate 6x=18-12 y and 7x+4y=9 need both x and y individually I really don't understand how to do it.
they are asking you to find the point of intersection for the 2 linear equations... it looks like you need to use the elimination method so take the 1st equation and divide every term by 6... as 6 is a common factor you get x = 3 - 2y for me, the easy method is to use substitution... so you take the equation above and substitute it into 7x + 4y = 9 or 7(3 - 2y) + 4y = 9 distribute and solve for y can you check the equation about and make sure it is = 9 and not = -9 when you find y, substitute it into either equation to find x. hope it helps
you could also graph the two lines and look at the point they intersect.
Or you can try the elimination method: 6x=18-12 y 7x+4y=9 Let's rearrange the 1st equation a) 6x +12y=18 b) 7x+4y=9 Multiply equation "b" by -3 a) 6x +12y=18 b) -21x -12y=-27 Adding both equations: -15x = -9 x = .6 and now you can easily solve for y
"eliminate 6x=18-12 y and 7x+4y=9 need both x and y individually" would be better written as "Solve the system of linear equations 6x=18-12y and 7x+4y=9 for x and y through elimination." In other words, eliminate one variable (by addition / subtraction or substitution, find the value of the other variable, and then use one of the above equations to find the 2nd unknown variable.