The fastest elevator in the world is in the Taipei 101 tower in Taiwan. Descending from the observation desk, the elevator travels between the two heights shown in about 7 seconds. ( heights are 1281 ft and 1057 ft ) a. Find the average space of the elevator, and graph the height against the time. b. Use your graph to estimate when the elevator will reach ground level.
Average space of the elevator? Or average speed?
Oh oops, I meant speed!
Alright! Well I'll do my best to help you answer this. A) Average speed. We know that speed is distance covered in a set amount of time. So we can see that they covered 224 feet (1281-1057) in only 7 seconds. Now we need to divide the distance by time to get a feet/second speed. 224/7 = 32 feet per second. B) To find how long before it will be on ground level take the total height (1281 ft) and divide that by 32 and you will end up with a number which is the total seconds it will take. So 1281/32 = 40.03 seconds.
Oh, thank you!! But how do I do the graph? Do I just start at 1281 ft and go down on the graph?
Yes. Start at 1281 and for every 1 second (x) you go, drop 32. So your equation should look something like f(x) = -32x+1281.
Okay, thank you so much!!!!
Anytime!
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