Question

3(2x + 5) ≥ 2(x + 6)

Answer 1

@Ninja4535

Answer 2

I'm stuck on this one

Answer 3

Any options?//

Answer 4

Give me a sec

Answer 5

3(2x + 5) ≥ 2(x + 6)
6x + 15 ≥ 2x + 12
6x + 15 - 2x ≥ 2x + 12 - 2x
4x + 15 ≥ 12
4x + 15 - 15 ≥ 12 - 15
4x ≥ -3
\[\frac{ 4x }{ 4 } ≥ \frac{ -3 }{ 4 }\]
x ≥ ?

This is as far as I've gotten.

Answer 6

There aren't options I need to solve for x

Answer 7

x=\[x=\ge - \frac{ 3 }{ 4 }\]

Answer 8

Oh...I feel dumb now. xD Thank you!

Answer 9

Lol