What is the oxidation state of Cr2 in K2Cr2O7?
\(\huge{Cr_{2}}\) in \(\huge{K_{2}Cr_{2}O_{7}}\)
points I noted: 1. there is no charge so net oxidation must be zero, 0 2. charge of K is -1, chromium has NO charge, oxygen is TYPICALLY -2 charge.
+6
1x2 +2x +(-2) x7 =0
I did 7(-2) for Oxygen and 2(1) for Potassium
and the \(\large{x}\) is the Chromium?
14-2=12 12/2=6
1* 2 +2x +(-2) * 7 =0
I got -12 charge. To counter is +12 and Cr is 2 so 12/2 is 6 Okay I got it
How about this one?\[\large{Fe_{3}O_{4}}\]
8/3
I think this: net is 0 O is 4(-2) ... yes that lol
okay I have an organic compound question -- how do I know when a compound is \(\Large{propanol}\)?
actually scratch that
has 3 C and one OH
how do I know when a compound is \(\Large{ethanoic}\) acid
sorry I figured out the propanol one, thanks though
CH₃COOH (acetic acid)
yes but how do I know to get that formula? is there any tips/tricks
also... Fe in \(\huge{Fe_{3}O_{4}}\) has a decimal oxidation...?
yes it is an average 2 atoms has oxidation of 3 and one oxidation of 2
so Fe has \(\approx+2\) oxidation
+2 and +3 depends with what they react, this it is a particular compound that has both https://en.wikipedia.org/wiki/Iron(II,III)_oxide
I saw .gif and expected an animation.... lol
But thank you :)
!!! I KNEW THE FORMULA I WROTE WAS BAD
gtg see you later
alright thank you :)
see ya~
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