Question

PLZ

Answer 1

@welshfella

Answer 2

an = 4 a^(n-1)

when n = 2
a2 = 4* (-6)*^1 = -24

now work out the third term ( where n = 3)

Answer 3

im not sure

Answer 4

a3=4*(3-1)

Answer 5

I have a lot of these to do could we maybe speed up the process :-)

Answer 6

@AAbomosalam1998

Answer 7

hold on
I might have misread the question.....

Answer 8

oh ok, thanks!

Answer 9

I've assumed that an-1 is a^(n-1) but it doesnt look like that.
Have you a picture of the original problem?

Answer 10

a1 usually means the first term of the sequence so it should be c or d. but i cant see how its either of these. Sorry.

Answer 11

The recurrence is actually
\[\begin{cases}a_1=-6\\\color{red}{a_n=4a_{n-1}}\end{cases}\]The first term is given to you, so you can eliminate two of the answer choices.

The next is \(a_2=4a_1=4(-6)=-24\).

The next is \(a_3=4a_2=4(-24)=\cdots\)

Answer 12

Oh right

Answer 13

so it would be: -24, -96, -384, -1536, -6144, -24,576

Answer 14

@welshfella

Answer 15

No -6 is the first term

its d

Answer 16

@welshfella please please help

Answer 17

@AAbomosalam1998 @HolsterEmission @mathstudent55 @karim728 please help me